Acube with edge = 1.00” of an unknown pure substance has a mas off 10.0 oz. what is the density of this substance in g/ml? in kg/l?

Answer 1) The density of the cube will be 17.30 g/mL

We know the edge that is 1 inch, we have to convert it into cc which will be;

1" = 16.38 cc and cc = mL

The given mass is in oz, we need to convert this as well in g;

10 oz = 283.495 g;

We have the formula as Mass = Density / Volume

Substituting the values; Density = (283.495 / 16.38) = 17.30 g/mL

So the density will be 17.30 g/mL

Answer 2) The density of cube will be 1.738 Kg/L

The same procedure of conversion would be done here,

Mass in Kg will be 0.02834 Kg and Volume will be 0.0163 L

On solving with the equation as Mass = Density /  Volume;

Density = (0.02834 / 0.0163) = 1.738 Kg/L

Hence, the density will be 1.738 Kg/L

the answer is d.) potassium

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