Asolution of an unknown nonvolatile nonelectrolyte was prepared by dissolving 0.250 g of the substance in 40.0 g of ccl4. the boiling point of the resultant solution was 0.357oc higher than that of the pure solvent. calculate the molar mass of the solute. (kb = 5.02oc/m)

Answer : The molar mass of the solute will be 87.90 g/mol.

Explanation : We know the formula for elevation in boiling point, which is

Δt = im

given that, Δt = 0.357, = 5.02 and mass of = 40,

on substituting the value we get,
0.357 = (1) X (5.02) X (x/ 0.044), on solving we get x = 2.844 X. 
Now, 0.250/ 2.844 X = 87.90 g/mol. which is the weight of unknown component.

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