In the reaction h2so4 + 2 naoh -> na2so4 + 2h2o, an equivalence point occurs when 34.23 ml of 0.2392 m naoh is added to a 38.34 ml portion of h2so4. what is the [h2so4]?

            moles NaOH = c · V = 0.2392 mmol/mL · 34.23 mL = 8.187816 mmol
            moles H2SO4 = 8.187816 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 4.093908 mmol
Hence
            [H2SO4]= n/V = 4.093908 mmol / 38.34 mL = 0.1068 M
The answer to this question is  [H2SO4] = 0.1068 M