What mass of oxygen (o2) is required to react completely with 86.17 grams of c6h14?

The balanced equation for the combustion of C₆H₁₄ is as follows
2C₆H₁₄ + 19O₂ ---> 12CO₂ + 14H₂O
stoichiometry of C₆H₁₄ to O₂ is 2:19
number of moles = mass present / molar mass 
number of C₆H₁₄ moles reacted = 86.17 g / 86 g/mol = 1.00 mol 
according to molar ratio of 2:19
2 mol of C₆H₁₄ reacts with 19 mol of O₂
then 1.00 mol of C₆H₁₄ reacts with - 19 / 2 x 1.00 = 9.5 mol of O₂
mass of O₂ required = 9.5 mol x 32 g/mol = 304 g
mass of O₂ required is 304 g

Ithink its called the coefficent.

Change of state has wrong energy change - option 2

brian made this table to organize his notes on changes of state. depostion is a change of state that has the wrong energy change listed. it is utilized to collect data as a portion of the development means and in restricted conditions which may be applied at test.

a deposition in the authority of the united states or research for development in the authority of canada includes the catching of affirmed. the out-of-court verbal assertion of a spectator that may be lessened to a printed record for succeeding application for discovery purposes.