What temperature in kelvin does 60.5 liters of sulfur dioxide occupy if there are 2.5 mol at 0.75 atm? ?

 The temperature  in kelvin  does  60.5  liters of sulfur  dioxide  occupy  if there  are  2.5  mole  at 0.75 atm  is   221.07  kelvin 

              Explanation
      This is  calculated using   ideal  gas  equation, that is  PV=nRT
where,  P(pressure)  = 0.75 atm
             V(volume)  = 60.5 L
             n(moles)  = 2.5 mole
             R( gas  constant) = 0.0821 L.atm/mol.k
            T(temperature  =?

by  making   T  the subject   of  the formula  
T  is  therefore =Pv/nR

T= (0.75 atm  x  60.5 L) / (  2.5 molex 0.0821  L.atm/mol.K)  = 221.07 kelvins

You need to divided twenty four by a dozen them by the temperature it is getting cook by