To prepare a 2 m solution of the hbr titrant, you need 2 moles of hbr and 1 liter of water. how much hbr will you weigh out on the scale and dissolve in the 1 liter of water to prepare the solution?

Molecular weight of HBr =  80.91 g/mol.

We know that, 1 mole of HBr = 80.91 g/mol
Therefore, 2 mole of HBr = 80.91 x 2
                                         = 161.82 g.

Hence, 161.82 g of HBr should be dissolved in 1 liter solution, to obtain 2 M solution.

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