If the mole fraction of k2so3 in an aqueous solution is 0.0328 what is the weight/weight % of k2so3

Explanation:

Hello,

In this case, since potassium sulfite is in an aqueous solution, that is water as solvent, one could assume 0.0328 moles of potassium sulfite and 1 mole of solution (total), therefore, the moles of water are:

Thus, one calculates each compound's grams by using their molar masses as:

Therefore, its weight/weight % turns out:

Best regards.

- both b and d.

-since b and d are the closest coastlines then that makes it the most affected.

< 3

the answer is c.the valence of the atoms combine .