If a 500.0-g block of metal absorbs 5,016j of heat when its temperature changes from 20.00 celcius, what is the specific heat?

Correction: The temperature change is from 20 °C to 30 °C.

               Cp  =  1.0032 J.g⁻¹.°C⁻¹

Solution:

The equation used for this problem is as follow,

                                                  Q  =  m Cp ΔT    (1)

Where;
            Q  =  Heat  =  5016 J

            m  =  mass  =  500 g

            Cp  =  Specific Heat Capacity  =  ??

            ΔT  =  Change in Temperature  =  30 °C  -  20 °C  =  10 °C

Solving eq. 1 for Cp,

                                 Cp  =  Q / m ΔT

Putting values,
                                 Cp  =  5016 J / (500 g × 10 °C)

                                 Cp  =  1.0032 J.g⁻¹.°C⁻¹