Read the passage below about different types of radiation. different types of radiation have different penetrating abilities. for example, gamma rays can pass through cloth and paper, but alpha particles are blocked by cloth and paper. beta particles are blocked by aluminum foil, but gamma rays are not. however, all three types of radiation are blocked by thick concrete or lead. now, examine a table of penetrating powers of different types of radiation. material 1 2 3 lead stopped stopped stopped cloth not stopped stopped stopped aluminum foil not stopped stopped stopped wood not stopped stopped stopped paper not stopped stopped not stopped thick concrete stopped stopped stopped based on the information, at which numbered spot in the table does each type of radiation belong?

In the given information all the radiations were stopped by the lead block, if we assume that first radiations were gamma radiation, as they were not stopped by the cloth whereas all other radiations were stopped.

In second case, aluminum foil and wood were able to block alpha and beta radiations. Whereas, paper was used to stop the alpha particles but not the gamma and beta rays. And then a thick concrete stopped all the radiations.

This clarifies that the first radiation are gamma rays, second is alpha rays and third is beta rays.

its d on edgd 2020

Explanation:

just took the test

it is called acid bonding

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years