Determine the number of moles of mg2+(aq) ions produced when 2.5 moles of zn 2+aq react completely in this cell

The question is incomplete. Complete question is attached below.

Solution:
The reaction involved in present electrochemical cell is:

Mg(s)     +       Zn2+(aq.)      ↔        Zn(s)      +      Mg2+ (aq.)

Thus, from above reaction it can be seen that 1 mole of Zn2+ produces 1 mole of Mg2+.

Thus, 2.5 moles of Mg2+(aq) ions would be produced when 2.5 moles of Zn2+(aq) will react.

; lc

Naoh + hbr -> nabr (salt) + h2o ca (oh)2 + 2hbr - - - > ca (br)2 + 2h2o