For a material that contains n atoms, how many electron states will there be in a p band

There will be 3N electron states in a p band.

Explanation:

In chemistry it is learned that under normal conditions atoms that have 4 electrons in the last valence shell are not stable. Semiconductors fall into this group, but because of the way in which they group their atoms, they can achieve stability by making four covalent chemical bonds, getting 8 electrons in the last shell, and consequently becoming chemically stable. However, semiconductors form Energy Bands. The above question is referring to a semiconductor.

Each energy level in a semiconductor splits, forming a series of atoms next to each other known as energy bands. The number of atoms within these bands will be equal to the sum of all equivalent atoms of the N atoms present in the semiconductor solid. For example, an s band will consist of N atoms and a p band of 3N atoms.

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when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol