What is the empirical formula of a compound that is 3.05% carbon, 0.26% hydrogen, and 96.69% iodine? question 4 options: chi3 ch2i5 c2hi7 c3h2i11?

Empirical formula is the simplest ratio of whole numbers of components in a compound 
calculating for 100 g of the compound 
                           C                                      H                                      I
mass                3.05 g                              0.26 g                                96.69 g
number of moles    3.05 g / 12 g/mol     0.26 g / 1 g/mol        96.69 g / 127 g/mol
                           = 0.254 mol                   = 0.26 mol                       = 0.7613 mol
divide by the least number of moles 
                       0.254/ 0.254 = 1.0      0.26 / 0.254 = 1.0      0.7613 / 0.254 = 2.99
when rounded off
C - 1
H - 1 
I - 3

empirical formula is CHI₃ 
answer 1) CHI₃