Calculate the solubility of silver oxalate, ag2c2o4, in pure water. ksp = 1.0 × 10-11 a. 1.4 × 10-4 m b. 8.2 × 10-5 m c. 5.4 × 10-5 m d. 3.2 × 10-6 m e. 2.5 × 10-12 m

Chemical reaction (dissociation) of silver oxalate in water: 
Ag₂C₂O₄(s) → 2Ag⁺(aq) + C₂O₄²⁻(aq).
Ksp(Ag₂C₂O₄) = [Ag⁺]²·[C₂O₄²⁻].
[C₂O₄²⁻] = x; solubility of oxalate ion.

[Ag⁺] = 2[C₂O₄²⁻] = 2x
1.0·10⁻¹¹ = (2x)² · x = 4x³.

x = ∛1.0·10⁻¹¹ ÷ 4.

x = 1.4·10⁻⁴ M.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.