The heat of combustion of ethane c2h6 is 1560 kj mol. what is the heat of combustion of ethane, in kj per gram

             51.88 kJ / g

Solution:

As we know 1 mole of ethane equals 30.07 g as,

                             C₂H₆  =  (12.01)₂ + (1.008)₆

                                      =  24.02 + 6.048

                        1 mole   =  30.068 g

Now, As heat of combustion of ethane C₂H₆ is,

                                      =  1560 kJ / mol

Substituting value of mole by gram,

                                      =  1560 kJ / 30.068 g

                                      =  51.88 kJ / g