The osmotic pressure of a solution formed by dissolving 45.0 mg of aspirin (c9h8o4) in enough water to make 0.250 l of solution at 25°c is atm

Answer is: osmotic pressure of aspirin is 0.025 atm.
m(C₉H₈O₄) = 45.0 ÷ 1000 mg/g = 0.045 g.
n(C₉H₈O₄) = m(C₉H₈O₄) ÷ M(C₉H₈O₄).
n(C₉H₈O₄) = 0.045 g ÷ 180 g/mol.
n(C₉H₈O₄) = 0.00025 mol.
c(C₉H₈O₄) = n(C₉H₈O₄) ÷ V(solution).
c(C₉H₈O₄) = 0.00025 mol ÷ 0.25 L.
c(C₉H₈O₄) = 0.001 M.
T = 25°C = 298.15 K.
R = 0.08206 L·atm/mol·K, universal gas constant.
p = c · R · T.
p = 0.001 mol/L · 0.08206 L·atm/mol·K · 298.15 K.
p = 0.025 atm.
 

The density of water is 1 g/cm cubed and in order for the pebble to sink its density has to be greater than the density of water and in order for the twig to float its density has to be less than the density of water

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