Chemistry, 20.07.2019 23:00, rscott400

What was the action between the 2 atoms in an ionically bonded compound that caused that ionic bond to form in the first place? mutual electrons interlocked attraction between electron cloud of one atom and nucleus of the other opposite ions attracted each other sharing of outer shell electrons

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Answers

  Opposite ions attraction between the 2 atoms in an ionically bonded compound causes the ionic bond to form in the first place.

Explanation:
Ionic bond is the electrostatic forces of attraction between positively charged cations and negatively charged Anions. These forces are very stronger resulting in increasing several physical properties of Ionic compounds like melting point and boiling point e.t.c.

Example:

Sodium Chloride:
NaCl is formed by Na⁺ cation and Cl⁻ anion as follow,

Oxidation of Na;

2 Na  → 2 Na⁺ + 2 e⁻

Reduction of Cl₂;

Cl₂ + 2 e⁻  → 2 Cl⁻

Crystal Lattice formation is as follow,

Na⁺ + Cl⁻ → NaCl

answered: Guest

1. 1 mole of anything contains 6.022x10^23 pieces

2. a

3. c, number

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br

molar mass = grams / number of moles = g/mole

to find moles = g / molar mass

to find mass = g = molar mass / moles

answered: Guest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.