Gas in a balloon occupies 3.3 l. what volume will it occupy if the pressure is changed from 100.0 kpa to 90.0 kpa (at constant temperature).

Boyle's law says "the pressure of a fixed amount of an ideal gas is inversely proportional to its volume when the temperature is constant".

P α 1/V

Where P is pressure of the gas and V is the volume of the gas.

Hence, we can use Boyle's law for two different situations as,

P₁V₁ = P₂V₂

P₁ = 100.0 kPa = 1 x 10⁵ Pa
V₁ = 3.3 L
P₂ = 90 x 10³ Pa
V₂ =?

By substitution,
    1 x 10⁵ Pa x 3.3 L = 90 x 10³ Pa x V₂
                            V₂ = 3.7 L

Hence, if the pressure drops from 100 kPa to 90 kPa, then the volume of the gas will be 3.7 L.

Here, we made an assumption as the gas is an ideal gas.

yes, water is wet, just as it makes other things wet, it is wet itself, kinda like ice, when ice is in water, the ice makes water cold, and ice is cold, therefore with that example, water is wet