A survey of entrepreneurs focused on their job characteristics, work habits, social activities, leisure time, etc. One question put to each entrepreneur was, "What make of car (U. S., Europe, or Japan) do you drive

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A survey of entrepreneurs focused on their job characteristics, work habits, social activities, leisure time, etc. One question put to each entrepreneur was, "What make of car (U.S., Europe, or Japan) do you drive?" The responses (number in each category) for a sample of 100 entrepreneurs are summarized below. The goal of the analysis is to determine if the proportions of entrepreneurs who drive American, European, and Japanese cars differ.

U.S. Europe Japan

40 35 25

In order to determine whether the true proportions in each response category differ, a one-way chi-square analysis should be conducted. Suppose the p-value for the test was calculated to be p=0.1738 . What is the appropriate conclusion to make when testing at α = 0.10?

Answer : The conclusion to be drawn is that We cannot reject the Null hypothesis if we use a one-way chi square analysis because at α = 0.1 from the chi-square  tabulated p-value = 0.584 while the calculated /given p-value is = 0.1738

Explanation:

Data given:

p-value = 0.1738

α = 0.10

sample size = 100

U.S cars = 40,      Europe cars = 35,   Japan cars = 25

The conclusion to be drawn is that We cannot reject the Null hypothesis if we use a one-way chi square analysis because at α = 0.1 from the chi-square  tabulated p-value = 0.584 while the calculated /given p-value is = 0.1738

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