A cafeteria serving line has a coffee urn from which customers serve themselves. Arrivals at the urn follow a Poisson distribution at the rate of 3.0 per minute. In serving themselves, customers take about 14 seconds, exponentially distributed. a. How many customers would you expect to see, on average, at the coffee urn? (Do not round intermediate calculations. Round your answer to 2 decimal places.)

3 customers.

Explanation:

Given the following :

Arrival rate of customers = 3 customers per minute

Service time = 14 seconds

Then if service time is 14 seconds, the service rate per minute will be 60/14 = 4.29 = 4 (nearest whole number)

Service rate = 4 customers per minute.

Number of customers at coffee urn(Nc) :

Nc = (arrival rate) /(service rate - arrival rate)

Nc = (3) / (4 - 3)

Nc = 3 / 1

Nc = 3

Therefore, average number of customers expected at coffee urn = 3

send the charted data

x=3

step-by-step explanation:

this is really simple i saw that there was only one term (5x) and thought if that was 15 what would i have to multiply everything else to get it there? well if 5x became 15 then x would have to be 3 so plug the 3 in the x for the other equations and you get 15 for the other ones. so there you go. : )