If a player chooses a mixed strategy in a Nash equilibrium, this implies that the payoff from using that mixed strategy is the same as the payoff from using any of the pure strategies in it. If the statement is true try to reason why, if it is false find a counterexample.

False.

Explanation:

The concept of "Nash equilibrium" is been by economist and also by "gamers" in game theory. Nash equilibrium is so good for making decisions and the determination of strategies.

In playing this game, the players or participants can use the pure strategy or the mixed strategy. The mixed strategy is the use of different strategies randomly.

"If a player chooses a mixed strategy in a Nash equilibrium, this implies that the payoff from using that mixed strategy is the same as the payoff from using any of the pure strategies in it".

The statement given above is FALSE because the PAYOFF WILL INCREASE IF WE ARE TO PLAY A MIXED STRATEGY.

For instance if we have a head of 1 and -1, and a tail of -1 and 1, the payoff for pure strategy is likely one or minus one but for a mixed strategy it could be zero.

answer; (identity theft);

all of them make sense but, i would have to say ask someone who has been there/or lives there, and/or read recent newspapers from that city.

hope this !