CraftWare Inc., a furniture manufacturer, uses ABC analysis to define its inventory value. The inventory contains wood, cast iron, adhesive, and carbon fiber. If wood accounts for 50 percent of the items and 5 percent of the total dollar value; carbon fiber accounts for 10 percent of the items and 60 percent of the total dollar value; cast iron accounts for 25 percent of the items and 18 percent of the total dollar value; and adhesive accounts for 15 percent of the items and 17 percent of the total dollar value, can be classified as a class C item.

a. adhesive
b. carbon fiber
c. cast iron
d. wood

Teller co. is planning to sell 900 boxes of ceramic tile, with production estimated at 870 boxes during may. each box of tile requires 44 pounds of clay mix and a quarter hour of direct labor. clay mix costs $0.40 per pound and employees of the company are paid $12.00 per hour. manufacturing overhead is applied at a rate of 110% of direct labor costs. teller has 3,900 pounds of clay mix in beginning inventory and wants to have 4,500 pounds in ending inventory. what is the total amount to be budgeted for manufacturing overhead for the month?

Which of the following accurately describes a surplus? a. consumer demand for a certain car is below the number of cars that are produced. b. the production costs for a certain car are below the sale price of that car. c. a reduction in the cost of steel enables a car company to reduce the sale price of its cars. d. a car company tries to charge too high a price for a car and has to reduce the price. 2b2t

Add the mips assembly language instructions (after main: ) to complete the following (in this order). do not skip steps. use other registers as needed. actions: 1. initialize the register $s0 to 35 2. prompt the user to enter a number, read the number and then put it into register $s1 3. prompt the user to enter a number, read the number and then put it into register $s2 4. store the value in $s1 into the memory at address 0x10010000. 5. store the value in $s2 into the memory at address 0x10010004. 6. calculate the value of $s0 - $s1 $s2 and store the result in the memory at address 0x10010008. 7. print the following output each on its own line. you will need to determine the location of each of the strings from the beginning of the memory segment a. your name b. the value in address 0x10010000 c. the value in address 0x10010004 d. the value in address 0x10010008 8. exchange or swap the values in $s1 and $s2 9. set the value in $s0 to -$s0