Under ideal conditions, a service bay at a fast lube can serve 77 cars per hour. the effective capacity of a fast lube service bay is 6.06.0 cars per hour, with efficiency known to be 0.850.85. the minimum number of service bays fast lube needs to achieve an anticipated production of 100100 cars per 88-hour day = nothing service bays (enter your response rounded up to the next whole number).

The minimum number of bays to achieve an anticipated production of 100 cars per hour day is 3.

Explanation:

The numbers seem to be doubled.

We have the following informations:

The effective capacity of a Fast Lube service bay is 6.0.

The efficience is 0.85.

We have that

Expected output = effective capacity * efficience

Expected output = 6*0.85

Expected output = 5.1

The expected output is 5.1 cars per hour.

In an 8 hour day, that is: 8*5.1 = 40.8 cars.

This means that 1 bay can do 40.8 cars.

Now, we solve a rule of three to find how many bays we need for 100 cars.

1 bay - 40.8 cars

x bays - 100 cars

The number of bays is a discrete number, this means that the minimum number of bays to achieve an anticipated production of 100 cars per hour day is 3.

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