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Business, 18.09.2019 04:30, anthonypacheco

Compute lequals=left parenthesis startfraction k over 100 endfraction right parenthesis times n k 100•n, where n is the total number of values in the data set and k is the percentile being used. l is a locator that gives the position pk, the kth percentile. if l is a whole number, the value of the kth percentile is midway between the lth value and the next value in the sorted set of data. if l is not a whole number, change it by rounding up to the next largest whole number, and the value of the kth percentile is this value.

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Mathematics, 05.09.2019 21:30, mamacita712

Sharon worked hard for a long time to save the money for a new car. she has budgeted between $15,000 and $20,000 for the new car plus the cost of gas for a year. let x represent gas mileage. which compound inequality represents the gas mileage that a $12,000 car can get and still fit in her budget if gas costs $4 per gallon and she drives 15,000 miles a year? 15,000 ≤ 12,000 + 415,000 less than or equal to 12,000 plus 4 left-parenthesis startfraction 15,000 over x endfraction right-parenthesis less than or equal to 20,000. ≤ 20,000 15,000 < 12,000 + 415,000 less than 12,000 plus 4 left-parenthesis startfraction 15,000 over x endfraction right-parenthesis less than 20,000. < 20,000 15,000 ≤ 12,000 + x15,000 less than or equal to 12,000 plus x left-parenthesis startfraction 15,000 over 4 endfraction right-parenthesis less than or equal to 20,000. ≤ 20,000 15,000 < 12,000 + x15,000 less than 12,000 plus x left-parenthesis startfraction 15,000 over 4 endfraction right-parenthesis less than 20,000. < 20,000

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Mathematics, 16.10.2019 01:00, Lydiac9243

Which linear equations have an infinite number of solutions? check all that apply. (x – ) = (x – left-parenthesis x minus startfraction 3 over 7 endfraction right-parenthesis equals startfraction 2 over 3 endfraction left-parenthesis startfraction 3 over 2 x endfraction minus startfraction 9 over 14 endfraction right-parenthesis.) 8(x + 2) = 5x – 14 12.3x – 18 = 3(–6 + 4.1x) (6x + 10) = 7(startfraction one-half endfraction left parenthesis 6 x plus 10 right-parenthesis equals 7 left-parenthesis startfraction 3 over 7 x minus 2 right-parenthesis.x – 2) 4.2x – 3.5 = 2.1 (5x + 8)

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Mathematics, 05.11.2019 03:31, christopherluckey7

which linear equations have an infinite number of solutions? check all that apply. (x – ) = (x – left-parenthesis x minus startfraction 3 over 7 endfraction right-parenthesis equals startfraction 2 over 3 endfraction left-parenthesis startfraction 3 over 2 x endfraction minus startfraction 9 over 14 endfraction right-parenthesis.) 8(x + 2) = 5x – 14 12.3x – 18 = 3(–6 + 4.1x) (6x + 10) = 7(startfraction one-half endfraction left parenthesis 6 x plus 10 right-parenthesis equals 7 left-parenthesis startfraction 3 over 7 x minus 2 right-parenthesis.x – 2) 4.2x – 3.5 = 2.1 (5x + 8)

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