Sam makes a deposit at the bank which is comprised of $5, $10, and $20 bills. if the number of $5 bills is three more than the number of $10 bills, the number of $20 bills is half the number of $5 bills, and his total deposit is $270, how many bills of each type did he deposit?

Number of $5 bills= 12

Number of $10 bills= 9

Number of $20= 6

Explanation:

Giving the following information:

Total deposit= $270

$5 bills are three more than the number of $10 bills.

The number of $20 bills is half the number of $5 bills.

x1= number of $5 bills

x2= number of $10 bills

x3= number of $20 bills

x1=3+x2

x3=x1/2

The function to calculate the number of bills is:

Total number of bills= (3+x2)*$5 + x2*$10+ (x1/2)*$20

n$x1n$x2n$x3  

42011024070

5252202,55095

630330360120

7354403,570145

840550480170

9456604,590195

10507705100220

11558805,5110245

12609906120270

x1= 12

x2= 9

x3=6

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