If you examine a population for a particular gene where b represents the dominant allele and b represents the recessive allele, you find that the allele frequencies for this gene are p = 0.3 and q = 0.7. if this population is not evolving, what would be the frequency of the heterozygous genotype? a. 0.09 b. 0.21 c. 0.30 d. 0.42 e. 0.49

Assuming Hardy-Weinberg equilibrium

B=dominant, P(B)=0.3
b=recessive, P(b)=0.7

Genotypes are given by:

(P(B)+P(b))^2=(0.3+0.7)^2=0.3^2+2*0.3*0.7+0.7^2=0.09+0.42+0.49=1

                                                                                         P(BB)+P(Bb)+P(bb)=1

Which means

P(BB)=0.09   (homozygous dominant genotype)

P(Bb)=0.42   (heterozygous genotype)

P(bb)=0.49   (homozygous recessive genotype)

archaebacteria are found in in forest soil.

hope i spelled it right lol

hope i

-lavira: )

both male and female gametes are produced by meiosis of the germ cells. therefore, both male and female gametes are haploid. one male and one female gamete unite during the fertilization to form the diploid zygote. in seed bearing plants, pollen grain is the male gametophyte, which produces sperm cells.