Acheckered hen mates with a checkered rooster. the genes for the checkered trait are codominant in both parents. what are the chances that their offspring will be checkered? 20% 25% 50% 75% 100%

Option D, 75%

Explanation:

Let the genotype of co dominant checkered hen mates and checkered rooster be CcC and CcC

Where Cc – is the allele for chekered skin  

C – is the allele for non chekered skin

Co-dominant allele are those which irrespective of being dominant or recessive are expressed equally.  

The punnet square for the cross between these two would be  

CcC

CcCcC

CCCc          CC

3 out of 4 offsprings have chekered allele i.e , CcC and CcC. Thus, the probability of chekered offsprings would be 75%

The correct answer is option - 75%.

Explanation:

Codominance is is trait or the relation between two type of gene. Generally genes have dominant or recessive type called alleles if both type of alleles  that is present in offspring in normal pattern of inheritance only dominant expressed in the offspring.

In co dominance bot the alleles expressed equally  in the offspring if present together so it can be understand by that when there is no allele shows it neither dominant nor recessive and both expressed equally is known as co dominance.

In this case genotype of co dominant checkered hen mates and checkered rooster should be CˣC and CˣC.

(assume Cˣ– is the allele for chekered skin and C – is the allele for non chekered skin)

     Cˣ        C

Cˣ  Cˣ Cˣ  CˣC

C   Cˣ C     CC

Calculating it  with the help of punnet square it is found that 3 out of 4 offsprings have chekered allele i.e CˣCˣ, CˣC and CˣC.

Thus, the probability would be 75% for checkered offsprings.

answer; i do believe that the correct answer is; ///mendelian genes are at specific loci on the chromosome and, in turn, segregate during meiosis;