In a dihybrid cross with genotypes jjqq and jjqq, what is the probability of getting an offspring with genotype jjqq?  

1/4

Explanation:

A dihybrid cross is a cross between two individuals in which two different traits are analyzed.

In the problem, the genes are J/j and Q/q.

To analyze the genotypes of the offspring, a Punnett Square is needed. See the image attached. If you count them, the genotype JjQq appears 2 out of 8 times, so the probability of getting that genotype in the offspring is 2/8 = 1/4.

oxygen = 21% of the atmosphere

nitrogen = 78%

carbon dioxide = 0.1%

argon =0.934%

answer///multiple alleles;