Suppose that an adult black bear adds 50 pounds of fat in order to survive while hibernating through the winter. how much glycogen would a bear have to add to achieve a similar feat?

The correct answer would be 112.5 pounds

Explanation:

Let us first covert the pound into grams. We know that 1 pound is equal to 453.59 grams.

Thus, 50 pound of fat = 50 x 453.59 = 22,679.5 grams.

We know that, 1 gram of fat releases 9 Kcal of energy. Thus, total energy produced by 22679.5 grams = 9 x 22679.5 = 204,115.5 Kcal

Glycogen is carbohydrate thus, it will produce 4 Kcal of energy per gram.

Thus, 4 x C = 204,115.5 (where C is the grams of glycogen)

⇒ C =

⇒ C = 51,028.875 grams

Using 1 pound = 453.59 grams, we con convert 51,028.875 grams into pounds:

453.59 = 1

1 =

51,028.875 =

= 112.5 pounds

Thus, 112.5 pound of glycogen would be needed to produce the same amount of energy as produced by 50 pounds of fat.

gametes or germ cells are haploid cells (example: sperm and ova) containing only one set (or n) number of chromosomes and autosomal or somatic cells are diploid cells containing 2n number of chromosomes.