What is the probability that a hybrid individual with the genotype AabbCcddEeFf will produce a gamete that has the genotype abCdeF

6.25%

Explanation:

Find the number of different gametes that can be produced

number of gametes produced = 2^n

n is the number of allele pairs that are heterozygous

there are 4 heterozygous allele pairs, these are: Aa, Cc, Ee and Ff

2^4 = 16

abCdeF is one of the 16 genotypes that could be produced

to find the percentage, divide 1 and 16 and multiply by 100

1 ÷ 16 = 0.0625

0.0625 × 100 = 6.25

a

explanation:

hey bro i looked it up on google the structure of the eye-spot in euglena viridie, e. ehrenbergii, and phacus pyriyorme is not as franzé haa described it. the so-called “crystal body” and “lens bodies” were not found in any of the individuals of the species examined by me. as earlier observers have stated, the eye-spot consists simply of a mass of pigment granules arranged in a single layer, and probably embedded in a protoplasmic framework, but the latter could not be seen, and its presence was only inferred from the fact that the pigment granules must be held together in some way, thd the eye-spot as a whole is capable of expansion, and that the pigment granules can be separated from each other.

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