A person with curly hair has children with a person who has straight hair. All children in the F1 generation have wavy hair. What kind of inheritance pattern explains this phenomenon? What would the F2 generation look like, i. e., what would the genotype and phenotype ratios be if two wavy haired individuals had children

The correct answer is -

a. incomplete dominance

b. f2 = 1:2:1 = straight:wavy:curly

Explanation:

In this question, it is given that a person with curly hair and a person with straight hair has all children with wavy hair. It means that the heterozygous offspring in F1 has blended traits which means this trait shows incomplete dominance. Suppose C is curly hair c is straight hair then f1 offspring will have Cc (wavy hair)

now in F2:

cross: Cc cross with Cc

gametes: C, c

Punnett square:

   C       c

C    CC    Cc

c    Cc     cc

Thus, the genotype and phenotype ration would be :

genotype: 1:2:1 = CC:Cc:cc

phenotype: 1:2:1 = straight:wavy:curly

enzyme speed up the reactions

tsd is temerature dependent sex determination.

tsd: it is a type of environmental sex determination in which the temperature experienced during embryonic/ larval development (ambient temperature for development) determine the sex of the offspring.

crocodile displays the tsd where the ambient temperature of the developing egg determines the individual's sex. for example in the american alligator's eggs, incubation at 33 ºc produces mostly males, while incubation at 30 ºc produces mostly females. so if the american alligator's egg will get the ambient temperature (33 degree celcius)during embryonic development from egg, the offspring will be male and same for the female sex determination.