ndividuals III-6 and III-7 have two little monstersand are expecting a third one. Their two childrenhave two eyes. What is the chance that the third child willhave one eye

The correct answer is - 75% or 3/4.

Explanation:

In the given question, there is a cross between III-6 and III-7 that produced two double eyes monsters and expected one more. As given in the image that the A or single eye is dominant over the a or double eye then both parents must be heterozygous as they produced double eye offspring (aa) and they do have only one eye.

then chances of single eye offspring would be -

cross: Aa and Aa

gametes: A, a and A, a

Punnett square:

           A      a

A         AA     Aa

a         Aa      aa

so there are 75% chances to have a single eye and 25% chances for a double eye.

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