Determine the probability of producing light colored moths if a heterozygous dark male is crossed with a light female moth

1/2 or 50%

Explanation:

Let us assume that the existence of heterozygous dark male means that the dark trait is dominant over the light trait. Hence, the light color trait is recessive.

Let us also assume that the dark color trait is represented by the allele A and the light color trait by allele a.

Heterozygous dark male = Aa

Light female = aa

Crossing the two:

            Aa    x    aa

         Aa   Aa   aa   aa

Aa = dark color = 1/2 or 50%

aa = light color = 1/2 or 50%

Hence, the probability of producing light-colored moths would be 1/2 or 50%.

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