In horses, black coloring (B) is dominant, and chestnut coloring (b) is recessive. What percentage of offspring are expected to be chestnut?

This question is incomplete, the complete question is as follows:

- In horses, black coloring (B) is dominant, and chestnut coloring (b) is recessive. A homzygous black horse crosses with a chestnut horse.

What percentage of offspring are expected to be chestnut?

The answer is 0%

Explanation:

This question involves a gene coding for color in horses. The allele for black coloring (B) is dominant over the allele for chestnut coloring (b) is recessive.

According to this question, if a homzygous black horse (BB) crosses with a chestnut horse (bb), the following gamete will be produced by each parent;

BB - B only

bb - b only

Using these gametes in a punnet square, the following proportion of offsprings will be produced:

Bb, Bb, Bb, Bb

All of these offsprings are phenotypically black colored although heterozygous in genotype. Hence, 0%  of offspring are expected to be chestnut.

step 1: initiation

initiation is the beginning of transcription. it occurs when the enzyme rna polymerase binds to a region of a gene called the promoter. this signals the dna to unwind so the enzyme can ‘‘read’’ the bases in one of the dna strands. the enzyme is now ready to make a strand of mrna with a complementary sequence of bases.

step 2: elongation

elongation is the addition of nucleotides to the mrna strand. rna polymerase reads the unwound dna strand and builds the mrna molecule, using complementary base pairs. there is a brief time during this process when the newly formed rna is bound to the unwound dna. during this process, an adenine (a) in the dna binds to an uracil (u) in the rna.

step 3: termination

termination is the ending of transcription, and occurs when rna polymerase crosses a stop (termination) sequence in the gene. the mrna strand is complete, and it detaches from dna.

it would be heredity