We have 16g of helium and the molar mass of He is 4.002 Amu.
Mole = 16g/4.002Amu
Mole = 3.998 mol
Mole = 4.00 mol
There are 6.02 x 10^23 molecules in a mol so there are 4 times of 6.02 x 10^23 molecules of helium. Quite a lot huh! :)
The other person should of stopped there they started making up steps XD
16/4 = 4
4 moles of He
We have, 16g of He (Helium).
To calculate the number of moles in given amount of a substance, we have the formula.
Here, we have 16g of He.
Molar mass of He is 4g
On substituting the values in the equation, we get
Answer : The moles of formed are, 22.3 moles.
Explanation : Given,
Moles of = 16.72 mol
The given chemical reaction is:
From the balanced chemical reaction, we conclude that:
As, 3 moles of react to give 4 moles of
So, 16.72 moles of react to give moles of
Therefore, the moles of formed are, 22.3 moles.
the answer is:
B. 4.0 mol
hope this helps :)
M = 56 * 2 + 16 * 3 = 160g/mol
n = m/M = 161g / 160g/mol = 1,00625 mol
1 mole MgS2O3 136.43 g
? moles MgS2O3 163 g
moles MgS2O3 = 163 x 1 / 136.43
moles MgS2O3 = 163 / 136.43 => 1.1947 moles
the most speciallized is b. grizzly bear
helicase, i think thats it