This will be a two-trait question, so you will need to make a 4x4 Punnett square to solve this problem: In badgers, wide stripes across their face
are dominant to pinstripes, and long claws are dominant to short claws. A
hybrid, wide striped, long clawed badger mates with a pin-striped, hybrid
short clawed badger. Please provide the probabilities of the genotypes
and phenotypes going to be? Remember to use the F. O.I. L. method to
help you solve this.
Your answer

Genotype probabilities:

¼ WwLl, ¼ Wwll, ¼ wwLl, ¼ well

Phenotype probabilities:

- ¼ or 25% WwLl (wide-striped, long claws)

- ¼ or 25% Wwll (wide-striped, short claws)

- ¼ or 25% wwLl (pin-striped, long claws)

- ¼ or 25% wwll (pin-striped, short claws)

Explanation:

This question involves two different genes coding for stripes breadth and claw length respectively. The allele for wide stripes (W) across their face

are dominant to pinstripes (w), and long claws (L) are dominant to short claws (l).

According to this question, a hybrid wide striped and long clawed badger (WwLl) mates with a pin-striped and short clawed badger (wwll). The gametes produced by each parent in this cross is as follows:

WwLl - WL, Wl, wL, wl

wwll - wl, wl, wl, wl

Using this gametes to make a 4x4 punnett square (see attached image), the following proportion of offsprings will most likely be produced:

- ¼ or 25% WwLl (wide-striped, long claws)

- ¼ or 25% Wwll (wide-striped, short claws)

- ¼ or 25% wwLl (pin-striped, long claws)

- ¼ or 25% wwll (pin-striped, short claws)

Note that, the above illustration contains the phenotype and genotype probabilities.

not the best question format lol but what i think might as scale color is controlled by a single gene with two alleles, the green allele and the yellow allele. when moths that are homozygous for green scales are mated with moths that are homozygous for yellow scales, 100% of the offspring have green scales.

answer; /// i believe the correct answer is (reactants);