In dogs, the gene for fur color has two alleles. The dominant allele (F) codes for grey fur and the recessive allele (f) codes for black fur.

The possible % for FF genotype = 0% ; 50% for Ff ; 50% for ff

The possible % for phenotypes of Black fur is 50%; the possible % for Grey fur is 50%

The Mendelian theory explains the fundamental rules of how gene occurs in pairs and how they are passed down as separate units, from parent to offsprings. He studied the segregation of parental genes and how they manifested in offspring as dominant or recessive traits.

From the given information, we have:

Then;

The punnet square is used to show the crossing between the traits of the parent.

i.e.

           F          f

f           Ff        ff

f           Ff        ff

Then, the percentage % of the possible genotypes are:

The percentage of the possible phenotypes are:

Learn more about Mendelian Theory here:

link

% GENOTYPE

FF = 0%

Ff = 50%

ff = 50%

% PHENOTYPE

Black fur = 50%

Grey fur = 60%

Explanation:

This question involves a single gene coding for fur color in dogs. The allele for grey fur (F) is dominant over the allele for black fur (f). This means that a heterozygous dog (Ff) will have a grey fur.

In this question, a heterozygous female (Ff) is said to cross with a recessive male (ff) i.e. Ff × ff. The following gametes will be produced by each parent:

Ff - F and f

ff - f and f

Using these gametes in a punnet square (see attached image), the following genotypic proportion of offsprings will be produced:

Ff - 1/2 = 50%

ff - 1/2 = 50%

Ff is phenotypically GREY while ff is phenotypically BLACK. This means that 50% of the offsprings will be black and 50% will be grey.

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