Biology, 10.12.2020 18:50, marcucciisabella

1. Determina la masa de los reactivos y productos de la siguiente ecuación química 2C4H10 + 1302 → 8CO2 + 10H20 demostrando la ley de proporciones definidas. Datos: Carbono (C)
12g, Hidrogeno (H) 1g, Oxigeno (0)165 m

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1. Determina la masa de los reactivos y productos de la siguiente ecuación química 2C4H10 + 1302 → 8CO2 + 10H20 demostrando la ley de proporciones definidas. Datos: Carbono (C) 12g, Hidrogeno (H) 1g, Oxigeno (0)165 m

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1. Determina la masa de los reactivos y productos de la siguiente ecuación química 2C4H10 + 1302 → 8CO2 + 10H20 demostrando la ley de proporciones definidas. Datos: Carbono (C)
12g, Hidrogeno (H) 1g, Oxigeno (0)165 m