Potassium thiosulfate (K2S2O3) is used to remove any excess chlorine from fibers and fabrics that have been bleached with that gas. The reaction is K2S2O3 + 4Cl2+ 5H2O→2KHSO4 + 8HCl a. What mass of HCl will be produced at the same time that 45.0 g of KHSO4 is produced? (5 pst) b. What mass of Cl2 is consumed along with 2.20 x 1024 molecules of H2O? (5 pts)

The correct answer is a) 48.16 grams of HCl will be produced, b) mass of chlorine consumed is 206 grams.

Explanation:

a) The reaction given is:

K₂S₂O₃ + 4Cl₂ + 5H₂O ⇒ 2KHSO₄ + 8HCl

Based on the given information, the mass of KHSO4 is 45 grams. The moles of KHSO4 can be determined by using the formula,  

Moles = given mass/Molar mass

= 45/136.16

= 0.33 Moles of KHSO₄

From the reaction it can be seen that when 2 moles of KHSO₄ is produced, 8 moles of HCl is also produced. Therefore,  

2 moles of KHSO₄ = 8 moles of HCl

So, moles of HCl will be,  

Moles of HCl = 8 × 0.33/2

= 1.321 moles

Now the mass of HCl is,  

Mass of HCl = Moles of HCl × Molar mass of HCl

= 1.321 × 36.46

= 48.16 grams of HCl

b) It is known that 1 mole is equal to 6.023 × 10²³ molecules

In the given case, the molecules of water is given, that is, 2.20 * 10²⁴ molecules. Now let us consider that the moles of water is x.  

x mole of water = 2.20 × 10²⁴ /6.022 × 10²³

= 3.653 mole of H2O

From the reaction given, it can be seen that when 5 moles of water are consumed, 4 moles of chlorine are consumed.  

5 moles of water = 4 moles of chlorine

3.653 moles H₂O = x moles of Cl₂

Moles of Cl₂ = 4 × 3.653 /5  

= 2.906 moles Cl₂

Now the mass of Cl₂ determined as,  

Mass of Cl₂ = moles of Cl₂ × Molar mass of Cl₂

= 2.906 × 70.9

= 206 grams