In a species of bird, the allele for the striped trait is recessive to the allele for the speckled trait. Suppose that a coastal bird population has a striped phenotype frequency of and an inland population has a striped phenotype frequency of The two populations are isolated and in Hardy–Weinberg equilibrium. Let represent the allele frequency of the coastal population and represent the allele frequency of the inland population. Calculate the allele frequency for the striped allele for each population. Round your answers to the nearest hundredth.

The answer is "0.42"

Explanation:

Please find the complete question in the attached file.

Coastal community striped allele intensity

Landlocked community, strip intensity allele

Its eliminated allele frequency for movement community And now in the sturdy vineyard optimum communities, genotype frequency of stripped characteristic (heterozygous device) in coasts

Heritable (striped) allele frecency:

(round up to the closest cent) is therefore the only frequency of coastal people.

The genome of pulling function in host population Heterozygous feature regularly.

Therefore the inland community rate of recessed (striped), allele rate:

Following migration;

Its percentage of coastal migrants:

Coastal population Non-immigrant percentage of coastal residents:

Stripping coastal community of allele rate after immigration:

the relative atomic mass of an element is the mass of one atom of that element, relative to 1/12th of the mass of a  1212c atom. to convert to an absolute mass in kg, it is necessary to multiply by  1.661×10−271.661×10−27.

the relative atomic mass is roughly equal to the number of neutrons, plus the number of protons, in the nucleus of the atom.

for elements with more than one stable isotope (different types of nucleus with different numbers of neutrons but the same number of protons), the quoted mass is usually the average mass, weighted by the relative abundance of the different isotopes.