When hydrogen nuclei are fused together to form a helium nucleus, the mass of the product is 0.7% less than the mass of the reactants. If 1 gram (1 x 10-3 kg) of protons were completely fused into helium nuclei, the mass of the helium nuclei
produced would be 6.8 x 10-6 kg less than the mass of the protons.
Using the equation E = mc2, calculate how many joules of energy would be produced by converting 6.8 x 10-6 kg of matter
into energy in this fusion reaction. Use c = 3 x 108 m/s.
E = 6.05 x 1011 kg x m²/s2
E = 6.10 x 1011 kg x m2/s2
E = 6.12 * 1011 kg x m2/52
E = 6.25 x 1011 kg * m/s2
E = 6.30 x 1011 kg m/s2