A researcher has a 50X Stock of TAE Buffer. The researcher needs to prepare 200 ml of 1X TAE Buffer. How will the researcher prepare this buffer? Be sure to include the amount of 50X TAE Buffer and dH2O used to prepare the buffer.

Volume of stock 50X TAE buffer required is 4 mL;

Volume of distilled water needed = 196 mL

The researcher will measure 4 mL of the stock 50X TAE solution using a pipette into a 250 mL volumetric flask. The researcher will then add 196 ml of distilled water to make it up to the 200 ml mark.

Explanation:

The following values are given: initial concentration, final concentration and final volume

Initial concentration,C₁ = 50X

Final concentration, C₂ = 1X

Final volume, V₂ = 200 mL

Initial volume, V₁ = ?

Using C₁V₁ =  C₂V₂

V₁ = C₂V₂/C₁

V₁ = 1X * 200 mL/50X

V₁ = 4 mL

Therefore, volume of stock 50X TAE buffer required is 4 mL

Volume of distilled water needed = 200 mL - 4 mL

Volume of distilled water needed = 196 mL

The researcher will measure 4 mL of the stock 50X TAE solution using a pipette into a 250 mL volumetric flask. The researcher will then add 196 ml of distilled water to make it up to the 200 ml mark.

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