If the fatty acid palmitate (16:0) radiolabeled with 14C in C-16 were metabolized by mammalian cells under anaerobic conditions, what compounds would be tagged with 14C and in what position

The options are missing from the question,

Below are the options.

A) Tag would be CO2

B) Acetate in C-2

C) 1 uvate in C-3

D) pyruvate in C-3

E) oxaloacetate on C-1

F) palmitate in C-16

The correct answer to the question is option B

ACETATE IN C-2

If palmitate (16:0) which is a fatty acid radiolabeled with 14C in C-16, when metabolized under anaerobic conditions by mammalian cells,the compound that will be tagged with 14C will be ACETATE and the position it will be will be C-2

In an anaerobic condition, anaerobic CoA which is formed after the oxidation of fatty acid will now move into the Kreb cycle as a result of oxygen deficiency, taking the form of acetate,it will enter cytosol and will further be used for other purposes.

i think that c)gold was found there

but i am not sure

answer:

the water molecules are transferred from the roots to the stem or top parts of the tall tree because of important properties of water which are adhesion, cohesion and capillary action. cohesion is the property of water molecules keeps water molecules in a combined state by sharing of bonds between them at the atomic level. adhesion allows the interaction of water molecules with other substances or substrate. adhesion will cause the attachment of water molecules to the wall of the vessel (xylem) of the plant. capillary action occurs when the adhesive force to the vessel wall is stronger than the cohesive force between water molecules. capillary action mimics the transfer of water from a tube or pipe. in this way water utilizes its property to transfer water from down to top level of the plant.