What is the probability that the first offspring from the cross listed below will be heterozygous for all loci? aa Bb dd Ee x AA bb Dd Ee

Answer and Explanation:

Cross: aa Bb dd Ee x AA bb Dd Ee

We can calculate the probability of getting heterozygous individuals in the progeny by using the product rule. Assuming that these four genes assort independently (events that occur independently from each other), we can infer that the F1 will have the next genotypic proportions for each gene:

1) aa     x     AA

F1) 4/4=1 Aa

2)Bb    x    bb

F1) ½ bb

     ½ Bb

3)dd    x    Dd

F1) ½ dd

     ½ Dd

4)Ee    x    Ee

F1) ¼ EE

    2/4 = ½ Ee

     ¼ ee

So, to know what the probability is that the F1 of being heterozygous for all loci, we must multiply the respective individual probabilities of getting a heterozygous genotype, like this:  

1 Aa   x   ½ Bb   x    ½ Dd    x    ½ Ee = 1/8 AaBbDdEe

the correct answer is - d. china has a large and growing population.

the fact that china has a large (the biggest) population, and it is still growing, doesn't hinder the agriculture production in the country. in fact, it can for increased production in the agriculture, since there's more labor force, as well the sheer mass of people produces lots of scientists that come up with new inventions as to how to improve this sector. nice example is the inner mongolia region in china, in general dominated by the gobi desert, but few scientist came up with a nice idea as to how to make the region productive by using plants that are very resistant to droughts, so lots of people have been employed, and the region is becoming greener and greener each year, and the production of food in this region is also increasing.