Two students are working together to build a birdhouse. Student 1 applies a force of 10 N to a wooden board in order to slide it across the table to Student 2. If the force of friction resisting the student's push is 4 N, what is the net force acting on the board? A) 4N B) GN C) 10 N D) 14 N

Net force acting on the board = 6 N

Explanation:

Given:

Force acting by student 1 = 10 N

Force acting by student 2 = 4 N

Find:

Net force acting on the board

Computation:

Net force acting on the board = Force acting by student 1 - Force acting by student 2

Net force acting on the board = 10 N - 2 N

Net force acting on the board = 6 N

6N

Explanation:

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