Biology, 17.08.2020 01:01, amandarenee4296

Calculate the percentage loss of mass between the sucrose solutions 0.1 mol/dm3 and 0.5 mol/dm3. Give your answer to three significant figures

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answered: kassidy49

The percentage loss in mass between sucrose solutions 0.5 mol/dm³ and 0.1 mol/dm³ is 80.0% loss in mass

Explanation:

The molecular formula of sucrose is C₁₂H₂₂O₁₁

The molecular mass of sucrose is 342.3 g/mol

Therefore;

The mass of sucrose in 0.1 mol/dm³ solution = 0.1 × 342.3 = 34.23 g

The mass of sucrose in 0.5 mol/dm³ solution = 0.5 × 342.3 = 171.5 g

The percentage loss in mass of the sucrose is given as follows;

$Percentage \ loss \ in \ mass = \dfrac{Original \ mass - New \ mass}{Original \ mass } \times 100$

Therefore;

$Percentage \ loss \ in \ mass = \dfrac{171.5 - 34.23}{171.5} \times 100 = 80.04 \%$

Which gives, the percentage loss in mass between sucrose solutions 0.1 mol/dm³ and 0.5 mol/dm³ is 80.0% to three significant figures.

answered: Guest

hey, i believe your answer would be d. sugar ribose and the base uracil. i believe this is the answer, because rna consists of sugar ribose, adenine, guanine, cytosine, and uracil.

your first option is incorrect, because that's dna. where it consists of sugar deoxyribose, adenine, guanine, cytosine and thymine.

your second option is also incorrect, this is because sugar deoxyribose is in dna, and uracil is in rna. these two do not make sense together.

your third option being incorrect, because sugar ribose is in rna, but not the base of thymine. rna consists of uracil, not thymine.

lastly your fourth option being correct! this answer is correct, because both sugar ribose, and the base uracil are in rna! ~

answer is d. sugar ribose and the base uracil.

answered: Guest

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