The cross AB/ab X ab/ab produces the following progeny: AB/ab 391, ab/ab 401, aB/ab 406, Ab/ab 386. From these data, one can conclude that the A and B loci assort independently. A. True
B. False

B

Explanation:

The two loci did not assort independently.

In order to check for independent assortment or otherwise of the result from the cross, Chi-square is used to see if the result conforms with that of Mendelian standard of 9:3:3:1.

Phenotype           Observed f        Expected f               =

AB/ab                     391                  9/16 x 1584 = 891       = 280.58

ab/ab                     401                   3/16 x 1584 = 297     = 36.42

aB/ab                      406                  3/16 x 1584 = 297     = 40.00

Ab/ab                      386                   1/16 x 1584 = 99       = 832.01

Total = 280.58 + 36.42 + 40.00 + 832.01 = 1,189.01

Degree of freedom = 4 - 1 = 3

Tabulated at degree 3 freedom and 95% level = 7.815

The calculated value is more than the tabulated value. Therefore, we conclude that the outcome of the cross is not in agreement with Mendelian standard and hence, the A and B loci did not assort independently.

The correct option is B.

answer; i believe that the correct answer is (lung);

relative humidity, temperature and dew point -- are bound together in the mathematical relationship below. relative humidity changes when temperatures change. because warm air can hold more water vapor than cool air, relative humidity falls when the temperature rises if no moisture is added to the air. so i would say a