This requires you to use all the things we have learned in this chapter. 1.55 grams of Carbon disulfide is added to 2.83 grams of Oxygen to form Carbon dioxide and Sulfur dioxide. If the reaction yields
1.1 grams of the Sulfur dioxide what was the percent yield?
27%
14%
Ο Ο Ο Ο Ο
74%
42%
O 63%

The percent yield is, 42%

Explanation:

To calculate the moles :

The balanced chemical reaction is:

According to stoichiometry :

1 moles of require = 3 moles of

Thus 0.020 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 1 mole of give = 2 moles of

Thus 0.020 moles of give =  of

Theoretical mass of

Actual mass of = 1.1 g

Now we have to calculate the percent yield

Therefore, the percent yield is, 42%

b exhibiting favoritism toward the kikuyu people.

the answer is b. glad to .