A man who has male pattern baldness (X^bY) marries a woman who does not carry the allele (X^BX^B). What genotypic ratios would be expected of their children?

2:2

Explanation:

The genotypic ratio of expected of their offspring would be 2:2.

From the illustration, the genotype of the man with male pattern baldness is while the genotype of the woman without the baldness allele is .

Crossing the two genotypes in marriage:

                              x  

Progeny:              

Hence, the genotypic ratio of the offspring becomes:

2:2

i believe the correct answer is d