How many moles of oxygen are needed to burn 1.33 moles of methyl alcohol (ch3oh)?
2ch3oh + 3o2 2co2 + 4h2o

Well, it takes 3 moles of oxygen to completely burn 2 moles of methyl... 

So for every 2 moles of methyl, you need 1.5 times as much oxygen (3 divided by 2) 

That makes your ratio 1 : 1.5 

You need 1.33 moles of methyl so you multiply both sides of the ratio by 1.33 = 1.33 : 1.995 

 1.995 moles of oxygen are needed

It is platinum in the market value

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