The Manx cat has a very short or no tail due to a dominant trait T. Cats who inherit one dominant (T) and one recessive (t) allele will be tailless (Manx); cats who are homozygous recessive will have normal, long tails. However, the homozygous dominant condition (TT) is lethal—the embryo will not develop. If two Manx cats breed, what are the chances of Manx offspring or kittens with long tails?A. There will be no offspring at all, since none of the embryos will develop. B. All offspring will be Manx cats. C. All offspring will be kittens with long tails. D. Twice as many Manx as kittens with tails. E. Equal chance of Manx or kittens with tails.

.D. Twice as many Manx as kittens with tails

Explanation:

It is given that TT is lethal so we will not get any indviduals from this embryo, tt is normal and Tt is Manx cat.

Therefore, the  genotype of the Manx cat is Tt.

Now if we cross two Manx cats,

P ---> Tt X Tt we get,

F1 ---> TT Tt Tt and tt.

The TT genotype will be lethal genotype.

The Tt genotype will be the Manx cat.

The tt genotype will be the normal cat.

So we will have two Tt and one tt , that is two Manx cat and one normal cat.

Therefore, the number of Manx cat will be twice the number of normal cats.

D. Twice as many Manx as kittens with tails

Explanation:

because it is the correct answer

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